So if a full frame sensor has pixels 8.2 x 8.2 microns (The 5D) and a D2x has pixels 5.5 microns then the area difference is 67.2 square microns vs 30.25.. That means that according to the above, the 5D pixel will get 670 photons and have a S/N ratio of 134:1
Well, that scaling works only if we hold everything else constant -- S/N depends on sensor details and camera electronics, right?
Otherwise, we would have to conclude that because the D70 (23.7 by 15.6 with 6.1Mp for about 61 sq mics) would have better S/N than the 20D (22.5 by 15 with 8.2 Mp, 41 sq mics) and the D2X (30), and virtually the same as the 5D (67 vs 61 for the D70).
As a D70 shooter, I am painfully aware that it simply ain't so. Canon gets a better S/N out of a smaller sensor with a higher MP count, comparing the 20D to the D70. Superior engineering can break this scaling law -- and a truly superb small sensor can have better S/N than a larger sensor (again, with different materials and electronics).
Calculation is like masturbation. If you do it long enough, you start to think it's the real thing. Or so I hear.
I think I will go take pictures of ibises with my teeny sensor but oh-so-big 80-200 f2.8!
Cheers,
Chris



