I don't dispute that ... that is what I said ... strobe is stated as 80 degree, i.e. the cone of light coming out of strobe head is 80 degree ... fully understand that.
The Q ... is that the camera zoom effectively creates a cone of light that is received by the camera .... unfortunately that is given in mm not in degrees, so I am trying to figure out what 36mm equites to in terms of 'angle of view'
I had some time to run my equation through an excel spreadsheet to answer some of the questions here.
A lens system with an equivalent focal length of 36mm in air, or in water with a dome port, or in water with optics equivalent to a dome port will have:
vertical angle of view of 36.9 degrees
horizontal angle of view of 53.1 degrees
diagonal angle of view of 62 degrees
(see the equation in my post above)
If using a flat port in water and a 36mm equivalent lens, those numbers change to
vertical angle of view of 27.5 degrees
horizontal angle of view of 39.3 degrees
diagonal angle of view of 45.6 degrees
(see the equation in my post above, plus use Snell's Law to account for diffraction at the air-water interface)
Also note that all of these numbers (and angle of view numbers in general) apply at infinity. AOV is actually a little bit smaller at finite differences, although it doesn't really become significant until you get to macro distances. At really close distances, the fact that your camera's sensor is smaller than your flash's diffuser becomes more important than angle of view.